Said differently, the magnitude of the electric subject is equal to voltage divided by distance. We’re given a voltage of 4.5 kV, and also advised a journey distance of zero.5 m. Divide these two numbers and we have 9.zero kilovolts/meters. Now that’s handy isn’t it?! We knew coming in, our reply choices were going to have these items. In truth, we thought we’d have to use the precise numbers we did to unravel the issue before even thinking about any specifics.
Hydroxylation of benzoquinone This answer choice is attention-grabbing. Hydroxylation would introduce the necessary hydroxyl groups to the central ring, the identical way we see in hydroquinone. But our DHB has two hydroxyl teams and the carboxyl group. Correct answer is reply alternative A, the carboxylation of hydroquinone. 2) DHB was the coating on our plate in the passage, so we want to know the response that leads to its formation. That means we’ll want to go back to the passage and see our molecule, and we’ll doubtless have to know some properties about the molecule.
And the given problem resistance of the volt meter. Oil of the world meter is given as G capital G. And it’s unique vary insects range to read using linear regression determine the absorbance/concentration relationship for the dye. the potential. So the utmost current which is required here. It’s immediately full scale deflection and which is symbolized by I.
Here we see our diagram with the ions touring toward the MS detector. A low mass-to-charge ratio corresponds to a best velocity. We additionally know all ions journey a distance of zero.5 m to the detector, so we’ll doubtless have to clarify the speed distinction alongside the greatest way. Carboxylation of hydroquinone During carboxylation, a carboxylic acid group is produced by treating a substrate with carbon dioxide. Our DHB has two hydroxyl teams connected to reverse ends, but also a carboxyl group.
All three variants have the identical variety of base pairs; our correct answer is answer choice B. Purines are listed first for each reply choice, and the only reply selection that matches our prediction is reply choice A, there are 17 purines. We also mentioned there are 9 pyrimidines, so our answer choice checks out.
We can use exterior information to truly learn the plot and discover Vmax. We’re advised compound 1 produced beta-D-galactose a yellow Compound 2 with lactase. Visible mild is discovered at wavelengths within the excessive 300s to mid 700s. Yellow is within the center, at round 550 nanometers. If yellow is being observed in Compound 2, which means there might be absorption of the complementary color to yellow on the same time. The KM decreases and Vmax increases.
This means the folded construction of HPmutant is more compact than the opposite two. Biotinylated DNA strands are methylated at a higher rate than non-biotinylated DNA strands. This seems correct from the angle of our 509mer, however we’re solely going by the info in Figure 1. The biotinylated DNA is methylated at the identical fee as the non-biotinylated DNA strands.
